0=25x^2+50x+4

Solution for 0=25x^2+50x+4 equation:

0=25x^2+50x+4

We move all terms to the left:

0-(25x^2+50x+4)=0

We add all the numbers together, and all the variables

-(25x^2+50x+4)=0

We get rid of parentheses

-25x^2-50x-4=0

a = -25; b = -50; c = -4;
Δ = b2-4ac
Δ = -502-4·(-25)·(-4)
Δ = 2100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2100}=\sqrt{100*21}=\sqrt{100}*\sqrt{21}=10\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-10\sqrt{21}}{2*-25}=\frac{50-10\sqrt{21}}{-50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+10\sqrt{21}}{2*-25}=\frac{50+10\sqrt{21}}{-50}
$